A certain volume of Argon gas () requires to effuse through a hole. The same volume of another unkno — States of Matter and Gaseous State Chemistry Question
Question
A certain volume of Argon gas ($M = 40$) requires $45\text{ s}$ to effuse through a hole. The same volume of another unknown gas requires $60\text{ s}$ under identical conditions. The molecular weight of the unknown gas is:
Answer: C
💡 Solution & Explanation
$t_2 / t_1 = \sqrt{M_2 / M_1} \implies 60 / 45 = \sqrt{M / 40} \implies 4/3 = \sqrt{M / 40} \implies 16/9 = M/40 \implies M = 640/9 \approx 71.1$.
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