An amount of of a gaseous compound of boron and hydrogen occupies at and at . The compound is: (At. — States of Matter and Gaseous State Chemistry Question
Question
An amount of $1.00\text{ g}$ of a gaseous compound of boron and hydrogen occupies $0.820\text{ L}$ at $1.00\text{ atm}$ and at $30^\circ\text{C}$. The compound is: (At. wt: $H = 1.0, B = 10.8$)
Answer: C
💡 Solution & Explanation
Molar mass $M = wRT/PV = (1.00 \times 0.082 \times 303) / (1.00 \times 0.820) = 30.3\text{ g/mol}$. The molar mass of $B_2H_6$ is $(2 \times 10.8) + 6 = 27.6\text{ g/mol}$, which is the closest valid borane.
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