For of a real gas obeying the van der Waals equation, under conditions of low pressure and moderate β States of Matter and Gaseous State Chemistry Question
Question
For $1\text{ mole}$ of a real gas obeying the van der Waals equation, under conditions of low pressure and moderate temperature, the equation mathematically simplifies to:
Answer: B
π‘ Solution & Explanation
At low pressure, volume $V_m$ is large, making excluded volume '$b$' negligible ($V_m - b \approx V_m$). The equation $(P + a/V_m^2)V_m = RT$ rearranges to $P = RT/V_m - a/V_m^2$. Multiplying by $V_m/RT$ gives $Z = 1 - a/V_mRT$.
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