The average translational kinetic energy of a single molecule of an ideal gas at and pressure is mat — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

The total translational kinetic energy for $n$ moles is $(3/2)nRT$. For a single molecule, dividing by Avogadro's number $N_A$ yields $(3/2)(R/N_A)T = (3/2)kT$, where $k$ is the Boltzmann constant.