The average translational kinetic energy of a single molecule of an ideal gas at and pressure is mat — States of Matter and Gaseous State Chemistry Question
Question
The average translational kinetic energy of a single molecule of an ideal gas at $27^\circ\text{C}$ and $1\text{ atm}$ pressure is mathematically given by:
Answer: C
💡 Solution & Explanation
The total translational kinetic energy for $n$ moles is $(3/2)nRT$. For a single molecule, dividing by Avogadro's number $N_A$ yields $(3/2)(R/N_A)T = (3/2)kT$, where $k$ is the Boltzmann constant.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes