Equal masses of methane () and oxygen () are mixed in an empty container at . The fraction of the to — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Let the mass of each be $w$. Moles $n_{CH4} = w/16$, $n_{O2} = w/32$. Total moles = $3w/32$. The fraction of total pressure exerted by oxygen is its mole fraction: $(w/32) / (3w/32) = 1/3$.