The temperature at which the root mean square () speed of gas becomes exactly equal to the average s — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

$U_{rms}(SO_2) = U_{avg}(O_2) \implies \sqrt{3RT/64} = \sqrt{8R(300)/(32\pi)}$. Squaring both sides: $3T/64 = 75/\pi \implies T = 1600/\pi \approx 509.3\text{ K}$. In Celsius: $509.3 - 273.15 \approx 236^\circ\text{C}$.