Exactly of an unknown gaseous hydrocarbon on complete combustion gives of gas and of vapour under id — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

General equation: $C_xH_y + (x+y/4)O_2 \to xCO_2 + (y/2)H_2O$. From stoichiometry, $10x = 40 \implies x = 4$. For water, $10(y/2) = 50 \implies 5y = 50 \implies y = 10$. The hydrocarbon is Butane ($C_4H_{10}$).