Exactly of an unknown gaseous hydrocarbon on complete combustion gives of gas and of vapour under id — States of Matter and Gaseous State Chemistry Question
Question
Exactly $10\text{ mL}$ of an unknown gaseous hydrocarbon on complete combustion gives $40\text{ mL}$ of $CO_2$ gas and $50\text{ mL}$ of $H_2O$ vapour under identical conditions. The hydrocarbon is:
Answer: D
💡 Solution & Explanation
General equation: $C_xH_y + (x+y/4)O_2 \to xCO_2 + (y/2)H_2O$. From stoichiometry, $10x = 40 \implies x = 4$. For water, $10(y/2) = 50 \implies 5y = 50 \implies y = 10$. The hydrocarbon is Butane ($C_4H_{10}$).
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