At what temperature will the average speed of molecules possess the exact same value as that of mole — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Average speed $U = \sqrt{8RT/\pi M}$. Equating them: $\sqrt{T_{CH4}/16} = \sqrt{300/32} \implies T_{CH4}/16 = 300/32 \implies T_{CH4} = 300 \times (16/32) = 150\text{ K}$.