One litre of a gaseous mixture of two gases effuses in while of oxygen takes . The vapour density of — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Rate $r = V/t$. $r_{mix} = 1/311$. $r_{O2} = 2/1200 = 1/600$. By Graham's Law: $r_{mix}/r_{O2} = \sqrt{32/M_{mix}} \implies 600/311 = 1.929 = \sqrt{32/M_{mix}} \implies M_{mix} = 8.6$. Vapour Density = $M_{mix}/2 = 4.3$.