Solutions and Colligative PropertieshardMCQ SINGLE⭐ Must-Do

Calculate the mole fraction of glycerine () in a solution containing of water and of glycerine.Solutions and Colligative Properties Chemistry Question

Question

Calculate the mole fraction of glycerine ($C_3H_5(OH)_3$) in a solution containing $36\text{ g}$ of water and $46\text{ g}$ of glycerine.

Answer: B

💡 Solution & Explanation

Moles of water $= \frac{36}{18} = 2\text{ mol}$. Molar mass of glycerine $= 92\text{ g/mol}$. Moles of glycerine $= \frac{46}{92} = 0.5\text{ mol}$. Total moles $= 2 + 0.5 = 2.5$. Mole fraction of glycerine $= \frac{0.5}{2.5} = 0.2$.

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