can exist as several distinct hydrated coordination complexes. A aqueous solution of one specific is — Solutions and Colligative Properties Chemistry Question
Question
$PtCl_4 \cdot 6H_2O$ can exist as several distinct hydrated coordination complexes. A $1.0\text{ molal}$ aqueous solution of one specific isomer exhibits a freezing point depression of $3.72^\circ\text{C}$. Assuming $100\%$ ionization and $K_f = 1.86$, what is the correct formula of the complex?
Answer: C
💡 Solution & Explanation
First, find $i = \frac{\Delta T_f}{K_f \times m} = \frac{3.72}{1.86 \times 1} = 2$. An $i$ value of 2 means the complex dissociates into exactly 2 ions in solution. The only isomer that furnishes exactly one complex cation and one chloride anion ($1+1=2$) is $[Pt(H_2O)_3Cl_3]Cl \cdot 3H_2O$.
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