Determine the osmotic pressure () of a aqueous solution of at exactly . (Assume complete ionization, — Solutions and Colligative Properties Chemistry Question
Question
Determine the osmotic pressure ($\pi$) of a $0.585\% \text{ (w/v)}$ aqueous solution of $NaCl$ at exactly $27^\circ\text{C}$. (Assume complete ionization, $R = 0.0821\text{ L atm K}^{-1}\text{ mol}^{-1}$).
Answer: B
💡 Solution & Explanation
Concentration $C = \frac{0.585\text{ g}}{100\text{ mL}} = \frac{5.85\text{ g}}{1\text{ L}}$. Molarity $= 5.85 / 58.5 = 0.1\text{ M}$. For $NaCl$, $i=2$. Osmotic pressure $\pi = iCRT = 2 \times 0.1 \times 0.0821 \times 300 = 4.926\text{ atm}$.
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