The vapour pressure of pure water at is . If of pure glucose () is dissolved in of water, what will be the equilibrium vapour pressure of the resulting solution?

Question

The vapour pressure of pure water at $20^\circ	ext{C}$ is $17.5	ext{ mm Hg}$. If $18	ext{ g}$ of pure glucose ($C_6H_{12}O_6$) is dissolved in $178.2	ext{ g}$ of water, what will be the equilibrium vapour pressure of the resulting solution?

Prashant Kotian · Accepted Answer

Correct answer: A. Moles of glucose . Moles of water . Total moles . Mole fraction of water . By Raoult's law, .

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