Consider two volatile liquids A and B forming an ideal solution. If and are in the ratio , and their — Solutions and Colligative Properties Chemistry Question
Question
Consider two volatile liquids A and B forming an ideal solution. If $P^0_A$ and $P^0_B$ are in the ratio $1:3$, and their liquid phase mole fractions ($X_A$ and $X_B$) are also in the ratio $1:3$, what is the mole fraction of component A in the vapour phase ($Y_A$)?
Answer: C
💡 Solution & Explanation
Let $P^0_A = P$ and $P^0_B = 3P$. Let $X_A = 0.25$ and $X_B = 0.75$. Partial pressures are $P_A = P \times 0.25 = 0.25P$ and $P_B = 3P \times 0.75 = 2.25P$. Total pressure $P_{total} = 2.50P$. Mole fraction in vapour $Y_A = \frac{P_A}{P_{total}} = \frac{0.25P}{2.50P} = 0.10$.
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