Solutions and Colligative PropertieshardMCQ SINGLE⭐ Must-Do

At , the total vapour pressure (in mm Hg) of a methanol-ethanol solution is represented by the lineaSolutions and Colligative Properties Chemistry Question

Question

At $323\text{ K}$, the total vapour pressure (in mm Hg) of a methanol-ethanol solution is represented by the linear equation $P = 120 X_A + 140$, where $X_A$ is the mole fraction of methanol. What is the vapour pressure of pure methanol ($P^0_A$) at this temperature?

Answer: C

💡 Solution & Explanation

The total pressure equation is $P = P^0_B + (P^0_A - P^0_B)X_A$. To find the pure vapour pressure of methanol ($P^0_A$), we take the limit as its mole fraction $X_A \rightarrow 1$. Substituting $X_A = 1$ gives $P = 120(1) + 140 = 260\text{ mm Hg}$.

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