At , the total vapour pressure (in mm Hg) of a methanol-ethanol solution is represented by the linea — Solutions and Colligative Properties Chemistry Question
Question
At $323\text{ K}$, the total vapour pressure (in mm Hg) of a methanol-ethanol solution is represented by the linear equation $P = 120 X_A + 140$, where $X_A$ is the mole fraction of methanol. What is the vapour pressure of pure methanol ($P^0_A$) at this temperature?
Answer: C
💡 Solution & Explanation
The total pressure equation is $P = P^0_B + (P^0_A - P^0_B)X_A$. To find the pure vapour pressure of methanol ($P^0_A$), we take the limit as its mole fraction $X_A \rightarrow 1$. Substituting $X_A = 1$ gives $P = 120(1) + 140 = 260\text{ mm Hg}$.
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