Three gases A, B, and C have Henry's Law constants () in the order . What is the correct order of th — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

From Henry's Law $P = K_H \times \chi$, we see that $\chi = \frac{P}{K_H}$. At constant pressure, the mole fraction (solubility) is inversely proportional to $K_H$. Thus, the lowest $K_H$ yields the highest solubility, making the order B > C > A.