The density of a solution of acetic acid in water is . What is the molality of the solution? — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

Molality $m = \frac{1000 \times M}{1000 \times d - (M \times M_B)}$. Here, $M = 2.05$, $d = 1.02$, $M_B = 60\text{ g/mol}$. $m = \frac{1000 \times 2.05}{1020 - (2.05 \times 60)} = \frac{2050}{1020 - 123} = \frac{2050}{897} = 2.28\text{ m}$.