What is the exact mole fraction of the solute in a (molal) aqueous solution? — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

A $1.00\text{ m}$ aqueous solution contains $1\text{ mole}$ of solute in $1\text{ kg}$ ($1000\text{ g}$) of water. Moles of $H_2O = \frac{1000}{18} = 55.55\text{ moles}$. Mole fraction $\chi = \frac{1}{1 + 55.55} = \frac{1}{56.55} \approx 0.0177$.