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When alkali metals are heated in an excess of pure oxygen, they form different major products based s Block Elements Chemistry Question

Question

When alkali metals are heated in an excess of pure oxygen, they form different major products based on their size. Which of the following correctly pairs the metal with its major oxidation product?

Answer: B

💡 Solution & Explanation

Due to the stabilization of larger anions by larger cations (lattice energy effects), small $Li^+$ stabilizes the small oxide ion ($O^{2-}$), $Na^+$ stabilizes the peroxide ion ($O_2^{2-}$), and large $K^+$ (along with Rb and Cs) stabilizes the large superoxide ion ($O_2^-$).

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