Beryllium hydroxide, , is treated with an excess of aqueous Sodium Hydroxide (). What is the resulti — s Block Elements Chemistry Question
Question
Beryllium hydroxide, $Be(OH)_2$, is treated with an excess of aqueous Sodium Hydroxide ($NaOH$). What is the resulting complex formed in the solution?
Answer: B
💡 Solution & Explanation
$Be(OH)_2$ is amphoteric. While it reacts with acids to form beryllium salts, it also readily dissolves in excess strong alkalies like $NaOH$ to form the soluble beryllate complex anion, specifically Sodium beryllate, $Na_2[Be(OH)_4]$.
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