25 mL of household bleach solution ( ) was mixed with 30 mL of 0.50 M and 10 mL of 4 N acetic acid. In the titration of the liberated iodine, exactly 48 mL of 0.25 N (hypo) was used to reach the end p

Question

25 mL of household bleach solution ( $NaClO$ ) was mixed with 30 mL of 0.50 M $KI$ and 10 mL of 4 N acetic acid. In the titration of the liberated iodine, exactly 48 mL of 0.25 N $Na_2S_2O_3$ (hypo) was used to reach the end point. The molarity of the bleach solution is:

Prashant Kotian · Accepted Answer

Correct answer: C. This is an iodometric titration. Equivalents of Bleach = Equivalents of liberated = Equivalents of . The n-factor of (Cl goes from +1 to -1) is 2. . Since , .

💡 Solution & Explanation

Practice 22,000+ questions like this