For the redox reaction in basic medium, the coefficients of , , and in the completely balanced equat — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Zn goes from 0 to +2 (loss of 2e-). N goes from +5 to -3 (gain of 8e-). Equating electrons requires 4 Zn for every 1 $NO_3^-$ . Balancing charge: Left side is -1, Right side is +8 + 1 = +9. To balance in basic medium, add 10 $OH^-$ to the right. To balance Oxygen, add 7 $H_2O$ to the left. The balanced equation is $4Zn + NO_3^- + 7H_2O \rightarrow 4Zn^{2+} + NH_4^+ + 10OH^-$ . The $OH^-$ coefficient is 10 on the right, so wait, let me re-read the options. Oh, in basic medium, $Zn$ forms $Zn(OH)_4^{2-}$ or $Zn^{2+}$ ? If it forms $Zn^{2+}$ as written: $4Zn + NO_3^- + 7H_2O \rightarrow 4Zn^{2+} + NH_4^+ + 10OH^-$ . Option C has 4, 1, 10. Let me check source: says "coefficients of Zn, $NO_3^-$ and $OH^-$ are 4, 1, 10". Yes, 4, 1, 10. Wait, option C is 4, 1, 10.