In the balanced chemical reaction , the values of a, b, c, and d respectively correspond to: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$I^-$ oxidizes to $I_2$ losing 1e- per I. $IO_3^-$ reduces to $I_2$ gaining 5e- per iodine atom. Cross-multiplying to balance electrons gives $1 IO_3^- + 5 I^-$ . To balance O atoms, add $3H_2O$ to RHS. To balance H atoms, add $6H^+$ to LHS. Final: $IO_3^- + 5I^- + 6H^+ \rightarrow 3I_2 + 3H_2O$ .