Find the volume strength of the solution prepared by mixing 250 mL of 3N and 750 mL of 1N solution. — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

First, find the final normality of the mixture: $N_f = \frac{N_1V_1 + N_2V_2}{V_1 + V_2} = \frac{250 \times 3 + 750 \times 1}{1000} = \frac{750 + 750}{1000} = 1.5 N$ . The volume strength of any $H_2O_2$ solution is $5.6 \times N$ . Volume strength = $5.6 \times 1.5 = 8.4 V$ .