mL of solution is homogeneously mixed with mL of solution. The resulting molarity of the final mixtu — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$150$ mL of $6.00 M$ $H_2SO_4$ solution is homogeneously mixed with $250$ mL of $3.00 M$ $H_2SO_4$ solution. The resulting molarity of the final mixture is:
Answer: A
💡 Solution & Explanation
When mixing two solutions of the same solute, $M_f = \frac{M_1V_1 + M_2V_2}{V_1 + V_2}$ . $M_f = \frac{150 \times 6.00 + 250 \times 3.00}{150 + 250} = \frac{900 + 750}{400} = \frac{1650}{400} = 4.125 M$ .
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