For the redox reaction , the correct stoichiometric coefficients of , , and are respectively: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

The oxidation half-reaction is $C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-$ (multiply by 5). The reduction half-reaction is $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$ (multiply by 2). Adding them gives $2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O$ .