The oxidation number of Carbon in , , , , and are respectively: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Hydrogen has an O.S. of +1 and Chlorine has -1. Solving for C (x) in each: $CH_4$ gives $x+4=0 \Rightarrow -4$ ; $CH_3Cl$ gives $x+3-1=0 \Rightarrow -2$ ; $CH_2Cl_2$ gives $x+2-2=0 \Rightarrow 0$ ; $CHCl_3$ gives $x+1-3=0 \Rightarrow +2$ ; $CCl_4$ gives $x-4=0 \Rightarrow +4$ .