The oxidation states of the most electronegative element in the products of the reaction of with dil — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation states of the most electronegative element in the products of the reaction of $BaO_2$ with dilute $H_2SO_4$ are:
Answer: B
💡 Solution & Explanation
The products of the reaction are $BaSO_4$ and $H_2O_2$ . The most electronegative element is oxygen. In $BaSO_4$ , the oxidation state of oxygen is -2. In $H_2O_2$ (a peroxide), the oxidation state of oxygen is -1.
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