An alkyl halide is capable of undergoing both and mechanisms since both share the same initial rate-determining step. Which condition strongly shifts the reaction to favor the elimination pathway?

Question

An alkyl halide is capable of undergoing both $S_N1$ and $E1$ mechanisms since both share the same initial rate-determining step. Which condition strongly shifts the reaction to favor the $E1$ elimination pathway?

Prashant Kotian · Accepted Answer

Correct answer: C. High temperatures heavily favor elimination () over substitution () because elimination produces more product molecules (like an alkene + acid), leading to a favorable increase in system entropy ().

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