In Dumas' method, of an organic compound yielded of nitrogen gas collected at and pressure. If the a — Qualitative and Quantitative Analysis Chemistry Question
Question
In Dumas' method, $0.25 \text{ g}$ of an organic compound yielded $44 \text{ mL}$ of nitrogen gas collected at $300 \text{ K}$ and $725 \text{ mm Hg}$ pressure. If the aqueous tension at $300 \text{ K}$ is $25 \text{ mm Hg}$, what is the percentage of nitrogen in the compound?
Answer: B
💡 Solution & Explanation
Dry pressure = $725 - 25 = 700 \text{ mm Hg}$. $V_{STP} = (273 \times 700 \times 44) / (300 \times 760) = 33.52 \text{ mL}$. Mass of $N_2$ = $(28 / 22400) \times 33.52 = 0.0419 \text{ g}$. $\%N = (0.0419 / 0.25) \times 100 = 16.76\%$.
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