Complete combustion of an organic compound using the Dumas method yielded exactly 6 moles of , 4 mol — Qualitative and Quantitative Analysis Chemistry Question
Question
Complete combustion of an organic compound using the Dumas method yielded exactly 6 moles of $CO_2$, 4 moles of $H_2O$, and 1 mole of $N_2$ gas. Assuming the compound contains only C, H, and N, its empirical formula is:
Answer: B
💡 Solution & Explanation
6 moles of $CO_2$ gives 6 C atoms. 4 moles of $H_2O$ gives $4 \times 2 = 8$ H atoms. 1 mole of $N_2$ gives $1 \times 2 = 2$ N atoms. The molar ratio is C:H:N = 6:8:2. Thus, the empirical formula is $C_6H_8N_2$.
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