A pure aliphatic hydrocarbon undergoes complete quantitative combustion over to yield exactly of and — Qualitative and Quantitative Analysis Chemistry Question

💡 Solution & Explanation

Moles of Carbon = $3.08 \text{ g} / 44 \text{ g/mol} = 0.07 \text{ mol}$. Moles of Hydrogen atoms = $2 \times (1.44 \text{ g} / 18 \text{ g/mol}) = 0.16 \text{ mol}$. The molar ratio of $C:H$ is $0.07 : 0.16$, which normalizes to the integer ratio $7:16$. The empirical formula is thus $C_7H_{16}$.