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is precipitated in Group IV as a buff-colored sulphide. Boiling the solution with a strong oxidizingQualitative and Quantitative Analysis Chemistry Question

Question

$Mn^{2+}$ is precipitated in Group IV as a buff-colored sulphide. Boiling the $Mn^{2+}$ solution with a strong oxidizing agent like $PbO_2$ and concentrated $HNO_3$ yields a red-violet (purple) solution. This color is due to the formation of:

Answer: A

💡 Solution & Explanation

$PbO_2$ in concentrated $HNO_3$ is a powerful oxidizing environment that oxidizes $Mn^{2+}$ all the way to the $+7$ oxidation state, producing permanganic acid ($HMnO_4$), which exhibits the characteristic intense purple/red-violet color.

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