In the standard analysis of Group IV cations (), passing through a basic buffer () precipitates all four sulphides. If, instead, is passed through a strongly acidic solution () containing these same f

Question

In the standard analysis of Group IV cations ($Zn^{2+}, Mn^{2+}, Co^{2+}, Ni^{2+}$), passing $H_2S$ through a basic buffer ($NH_4OH/NH_4Cl$) precipitates all four sulphides. If, instead, $H_2S$ is passed through a strongly acidic solution ($>0.5	ext{ M HCl}$) containing these same four ions, what will precipitate?

Prashant Kotian · Accepted Answer

Correct answer: D. Group IV sulphides have relatively high values. The high concentration of in a solution strongly suppresses the ionization of (common ion effect). The resulting concentration is so incredibly low that it cannot exceed the for any Group IV sulphide, resulting in zero precipitation.

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