In Kjeldahl's estimation, the evolved ammonia is absorbed in a known volume () of standard acid of normality (). The unreacted acid is back-titrated with standard alkali (). The exact milli-equivalent

Question

In Kjeldahl's estimation, the evolved ammonia is absorbed in a known volume ($V_1$) of standard acid of normality ($N_1$). The unreacted acid is back-titrated with standard alkali ($N_2, V_2$). The exact milli-equivalents of $NH_3$ produced by the organic compound is mathematically given by the term:

Prashant Kotian · Accepted Answer

Correct answer: B. represents the total milli-equivalents of acid initially taken. represents the milli-equivalents of acid that remained unreacted. The difference between them, , perfectly corresponds to the milli-equivalents of acid that were neutralized by the evolved .

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