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The specific confirmatory test for phosphorus in an organic molecule involves fusing it with , boiliQualitative and Quantitative Analysis Chemistry Question

Question

The specific confirmatory test for phosphorus in an organic molecule involves fusing it with $Na_2O_2$, boiling with $HNO_3$, and treating the extract with ammonium molybdate. The resulting canary yellow precipitate has the exact stoichiometric formula:

Answer: A

💡 Solution & Explanation

The canary yellow precipitate is chemically known as ammonium phosphomolybdate. Its precise formula is $(NH_4)_3PO_4 \cdot 12MoO_3$, containing exactly 12 equivalents of molybdenum trioxide per phosphate unit.

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