Bismuth () ions react with dropwise potassium iodide () to yield a black precipitate. The continuous addition of excess to this mixture causes the precipitate to dissolve, forming a characteristic com

Question

Bismuth ($Bi^{3+}$) ions react with dropwise potassium iodide ($KI$) to yield a black precipitate. The continuous addition of excess $KI$ to this mixture causes the precipitate to dissolve, forming a characteristic complex solution of what color?

Prashant Kotian · Accepted Answer

Correct answer: B. The initial black precipitate is Bismuth(III) iodide (). Upon adding excess , it forms the soluble tetraiodobismuthate(III) complex ion, , which is distinctly orange in solution.

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