In the Carius method for halogens, of an organic compound gave of . The percentage of bromine in the — Practical Organic Chemistry and Purification Chemistry Question
Question
In the Carius method for halogens, $0.15\text{ g}$ of an organic compound gave $0.12\text{ g}$ of $AgBr$. The percentage of bromine in the compound is: (Atomic mass $Ag=108, Br=80$)
Answer: B
💡 Solution & Explanation
$\%Br = \frac{80}{188} \times \frac{\text{Mass of } AgBr}{\text{Mass of cmpd}} \times 100 = \frac{80}{188} \times \frac{0.12}{0.15} \times 100 = 34.04\%$.
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