In the Carius method, of an organic compound gave of . The percentage of sulphur in the compound is: — Practical Organic Chemistry and Purification Chemistry Question

💡 Solution & Explanation

$\%S = \frac{32}{233} \times \frac{\text{Mass of } BaSO_4}{\text{Mass of cmpd}} \times 100 = \frac{32}{233} \times \frac{0.582}{0.395} \times 100 = 20.24\%$.