In the Carius method, of an organic compound gave of . The percentage of sulphur in the compound is: — Practical Organic Chemistry and Purification Chemistry Question
Question
In the Carius method, $0.395\text{ g}$ of an organic compound gave $0.582\text{ g}$ of $BaSO_4$. The percentage of sulphur in the compound is: (Atomic mass $Ba=137, S=32$)
Answer: B
💡 Solution & Explanation
$\%S = \frac{32}{233} \times \frac{\text{Mass of } BaSO_4}{\text{Mass of cmpd}} \times 100 = \frac{32}{233} \times \frac{0.582}{0.395} \times 100 = 20.24\%$.
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