In Dumas' method, of a compound gave of at and . (Aqueous tension at ). The percentage of nitrogen i — Practical Organic Chemistry and Purification Chemistry Question
Question
In Dumas' method, $0.35\text{ g}$ of a compound gave $55\text{ mL}$ of $N_2$ at $300\text{ K}$ and $715\text{ mm Hg}$. (Aqueous tension at $300\text{ K} = 15\text{ mm}$). The percentage of nitrogen is:
Answer: C
💡 Solution & Explanation
$P_{\text{dry}} = 715 - 15 = 700\text{ mm}$. $V_{\text{STP}} = \frac{700 \times 55 \times 273}{760 \times 300} = 46.09\text{ mL}$. Mass = $\frac{28}{22400} \times 46.09$. $\%N = \frac{\text{Mass}}{0.35} \times 100 = 16.45\%$.
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