In Dumas' method, of an organic compound gave of collected at and . Given aqueous tension at is , th — Practical Organic Chemistry and Purification Chemistry Question
Question
In Dumas' method, $0.35\text{ g}$ of an organic compound gave $55\text{ mL}$ of $N_2$ collected at $300\text{ K}$ and $715\text{ mm Hg}$. Given aqueous tension at $300\text{ K}$ is $15\text{ mm Hg}$, the percentage of nitrogen is approximately:
Answer: C
💡 Solution & Explanation
$P_{dry} = 715 - 15 = 700\text{ mm}$. Using $V_{STP} = (700 \times 55 \times 273) / (760 \times 300) = 46.09\text{ mL}$. Mass = $(28/22400) \times 46.09$. $\%N = (\text{Mass}/0.35) \times 100 = 16.45\%$.
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