In Kjeldahl's method, of a compound was digested. The evolved was absorbed in of . Residual acid req — Practical Organic Chemistry and Purification Chemistry Question
Question
In Kjeldahl's method, $0.50\text{ g}$ of a compound was digested. The evolved $NH_3$ was absorbed in $50\text{ mL}$ of $0.5\text{ M } H_2SO_4$. Residual acid required $60\text{ mL}$ of $0.5\text{ M } NaOH$. The percentage of N is:
Answer: A
💡 Solution & Explanation
Initial acid mEq = $50 \times (0.5 \times 2) = 50$. Back-titrated base mEq = $60 \times (0.5 \times 1) = 30$. Acid consumed = $20\text{ mEq}$. $\%N = (1.4 \times 20) / 0.50 = 56.0\%$.
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