If phosphorus is estimated by precipitation as Magnesium ammonium phosphate and subsequent ignition — Practical Organic Chemistry and Purification Chemistry Question
Question
If phosphorus is estimated by precipitation as Magnesium ammonium phosphate and subsequent ignition to Magnesium pyrophosphate ($Mg_2P_2O_7$), what is the correct formula for the percentage of phosphorus?
Answer: B
💡 Solution & Explanation
The molar mass of $Mg_2P_2O_7$ is 222. Since there are TWO phosphorus atoms in the molecule, the mass of P is $2 \times 31 = 62$. Thus, the factor is $62/222$.
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