In Liebig's method, of a compound yielded of and of . What is the percentage of carbon in the compou — Practical Organic Chemistry and Purification Chemistry Question
Question
In Liebig's method, $0.2475\text{ g}$ of a compound yielded $0.4950\text{ g}$ of $CO_2$ and $0.2025\text{ g}$ of $H_2O$. What is the percentage of carbon in the compound?
Answer: A
💡 Solution & Explanation
$\%C = (12/44) \times (Mass\ of\ CO_2 / Mass\ of\ cmpd) \times 100$. So, $(12/44) \times (0.4950 / 0.2475) \times 100 = 54.54\%$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes