In steam distillation, the vapour pressure of water is and that of the organic compound () is . What — Practical Organic Chemistry and Purification Chemistry Question
Question
In steam distillation, the vapour pressure of water is $200\text{ mm Hg}$ and that of the organic compound ($M = 93\text{ g mol}^{-1}$) is $100\text{ mm Hg}$. What mass of the compound distils per $72\text{ g}$ of water?
Answer: A
💡 Solution & Explanation
Using the relation $W_1/W_2 = (P_1 M_1)/(P_2 M_2) \rightarrow 72/W_2 = (18 \times 200)/(93 \times 100)$. Solving yields $W_2 = 186\text{ g}$.
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