Diborane () undergoes asymmetrical cleavage when treated with small, unhindered bases. What is the product formed when it reacts with Ammonia () at low temperatures?

Question

Diborane ($B_2H_6$) undergoes asymmetrical cleavage when treated with small, unhindered bases. What is the product formed when it reacts with Ammonia ($NH_3$) at low temperatures?

Prashant Kotian · Accepted Answer

Correct answer: C. Small amines like cause asymmetrical cleavage of diborane, yielding the ionic salt . Upon heating this salt to 200°C, it converts to Borazine.

💡 Solution & Explanation

Practice 22,000+ questions like this