Diborane () undergoes asymmetrical cleavage when treated with small, unhindered bases. What is the p — p Block Elements Chemistry Question
Question
Diborane ($B_2H_6$) undergoes asymmetrical cleavage when treated with small, unhindered bases. What is the product formed when it reacts with Ammonia ($NH_3$) at low temperatures?
Answer: C
💡 Solution & Explanation
Small amines like $NH_3$ cause asymmetrical cleavage of diborane, yielding the ionic salt $[BH_2(NH_3)_2]^+ [BH_4]^-$. Upon heating this salt to 200°C, it converts to Borazine.
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