Xenon fluorides can act as powerful fluoride ion donors. When reacts with a strong Lewis acid like A — p Block Elements Chemistry Question
Question
Xenon fluorides can act as powerful fluoride ion donors. When $XeF_6$ reacts with a strong Lewis acid like Antimony pentafluoride ($SbF_5$), what is the exact nature of the resulting ionic complex?
Answer: C
💡 Solution & Explanation
$XeF_6$ acts as a fluoride donor to the strong Lewis acid $SbF_5$. It loses an $F^-$ ion to form the cationic xenon species $[XeF_5]^+$, while the acceptor atom becomes the fluoroanion $[SbF_6]^-$.
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