Xenon tetrafluoride () possesses 4 bonding pairs and 2 lone pairs of electrons. According to VSEPR t β p Block Elements Chemistry Question
Question
Xenon tetrafluoride ($XeF_4$) possesses 4 bonding pairs and 2 lone pairs of electrons. According to VSEPR theory, what is its precise hybridization and molecular shape?
Answer: B
π‘ Solution & Explanation
Xenon in $XeF_4$ has 6 electron domains (4 bond pairs + 2 lone pairs), resulting in $sp^3d^2$ hybridization. To minimize lone pair-lone pair repulsions, the two lone pairs occupy opposite axial positions, resulting in a perfect Square Planar molecular shape.
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