Heating orthoboric acid () at yields a compound X, which upon further heating to yields compound Y. — p Block Elements Chemistry Question

💡 Solution & Explanation

Heating $H_3BO_3$ to $100^\circ C$ removes a water molecule to form Metaboric acid ($HBO_2$). Heating to $160^\circ C$ further dehydrates it to Tetraboric acid ($H_2B_4O_7$). Strong red heat finally yields Boric anhydride ($B_2O_3$).