Natural Chlorine exhibits a fractional atomic weight of approximately . This is primarily due to the — Nuclear Chemistry and Radioactivity Chemistry Question
Question
Natural Chlorine exhibits a fractional atomic weight of approximately $35.5\text{ amu}$. This is primarily due to the natural abundance mixture of its two stable isotopes: ${}^{35}Cl$ and ${}^{37}Cl$. What is their approximate abundance ratio?
Answer: C
💡 Solution & Explanation
The fractional atomic weight is a weighted average. If ${}^{35}Cl$ is 75% abundant and ${}^{37}Cl$ is 25% abundant (a 3:1 ratio), the average mass is $[(35 \times 3) + (37 \times 1)] / 4 = 35.5\text{ amu}$.
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